x^2+3x=10300

Solution for x^2+3x=10300 equation:

x^2+3x=10300

We move all terms to the left:

x^2+3x-(10300)=0

a = 1; b = 3; c = -10300;
Δ = b2-4ac
Δ = 32-4·1·(-10300)
Δ = 41209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{41209}=203$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-203}{2*1}=\frac{-206}{2}
=-103
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+203}{2*1}=\frac{200}{2}
=100
$